1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Forced Oscillator where Damping is Negligible

  1. Jan 27, 2012 #1
    1. The problem statement, all variables and given/known data

    Damping is negligible for a 0.139 kg mass hanging from a light 7.00 N/m spring. The system is driven by a force oscillating with an amplitude of 1.88 N. At what frequency will the force make the mass vibrate with an amplitude of 0.430 m? There are two possible solutions, enter one of them.


    2. Relevant equations

    A = (Fo/m) / (√((ω^2 - ωo^2)^2 + (bω/m)^2)
    Damping is negligible, therefore b = 0, therefore
    A = (Fo/m) / (√((ω^2 - ωo^2)^2)

    ωo = √(k/m)


    3. The attempt at a solution

    So,
    m = 0.139 kg
    k = 7.00 N/m
    Fo = 1.88 N
    A = 0.430 m

    A = (Fo/m) / (√((ω^2 - ωo^2)^2)
    Rearranged to find ω, is

    (ω^2 - √(k/m)^2)^2 = (Fo/m) / A
    ω^2 = √((Fo/m)/A) + (k/m)
    ω = √( √((Fo/m)/A) + (k/m) )

    So,
    ω = √( √((1.88/0.139)/0.430) + (7/0.139) )
    ω = √( 1.77 + 50.3597)
    ω = 7.22 rad/s

    ω = 2(pi)f
    7.22 /2(pi) = f
    f = 1.49 Hz

    This is not the correct answer and I have no idea where I'm going wrong.

    Am I using the wrong equations? Are my calculations incorrect? Any assistance would be much appreciated.
     
  2. jcsd
  3. Jan 27, 2012 #2

    vela

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Education Advisor

    You simplified ##\sqrt{(\omega^2-\omega_0^2)^2}## incorrectly.
     
  4. Jan 27, 2012 #3
    How? I did the following:

    √((ω^2 - ωo^2)^2)

    Shouldn't the square root and the square cancel, leaving

    (ω^2 - ωo^2)

    ω^2 - (√k/m)^2

    ω^2 - (k/m)

    Resulting in:

    ω^2 = √((Fo/m)/A) + (k/m)

    Where did I go wrong?
     
  5. Jan 27, 2012 #4

    vela

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Education Advisor

    After setting b=0 and moving some stuff around, you should have
    $$A = \frac{F_0/m}{\sqrt{(\omega^2-\omega_0^2)^2}} = \frac{F_0/m}{\omega^2-\omega_0^2}$$My take was that you ended up with
    $$A = \frac{F_0/m}{\sqrt{(\omega^2-\omega_0^2)^2}} = \frac{F_0/m}{(\omega^2-\omega_0^2)^2}$$ (compare to "(ω^2 - √(k/m)^2)^2 = (Fo/m) / A" which is what you wrote in your first post) which leads to the incorrect answer.

    If you check the units on your result, you'll see they don't work out. That means you messed up the algebra somewhere.
     
  6. Jan 27, 2012 #5
    Ahh, yes, I see what I did. I did mess up the algebra without noticing. I had it straight in my head but not on paper.

    Thank you very much for pointing that out for me. I've got the correct answer now.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Forced Oscillator where Damping is Negligible
Loading...