Forces and Equilibrium : Find the force b/w the blocks?

AI Thread Summary
The discussion focuses on finding the force acting between two blocks moving up an inclined plane with constant velocity. The initial solution for the applied force (F) is determined to be 15 N by treating the blocks as a single system. To find the force between the blocks, a free-body diagram for the 1 kg block is suggested, considering the gravitational component along the slope. The weight of the 1 kg block is calculated as 10 N, leading to the conclusion that the normal force (N) exerted by the other block is 5 N. The conversation concludes with a successful resolution of the problem.
devvaibhav
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1. Two blocks are moved with constant velocity up the inclined plane with the help of force F as shown in the figure. Find the value of F and the force acting b/w the blocks.

02-1.jpg


Homework Equations


Nothing is given.


The Attempt at a Solution


I got the solution of the Force( F ) which is 15 N by considering the two blocks as a single system, making its F.B.D. and finding its components...The answer for F is correct. But i was unable to find the force acting b/w the blocks...Thanks. Waiting for an answer...
 
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Make a free-body diagram for the 1 kg block. You know the component of gravity along the slope, and an other force (call it N) is exerted on it by the other block.

ehild
 
ehild said:
Make a free-body diagram for the 1 kg block. You know the component of gravity along the slope, and an other force (call it N) is exerted on it by the other block.

ehild

thnx ehild
Wt. of 1 kg block= 10N
10sin30 = N
Therefore, N= 5 N...

Thank u so much...
 

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