Forces between two hanging parallel wires

AI Thread Summary
The discussion focuses on calculating the current (I) in two hanging parallel wires using free body diagrams and relevant equations. The initial setup involves balancing forces in both the vertical and horizontal directions, leading to a calculated current of 594A. Participants confirm the accuracy of this value, with one noting a slight variation due to significant digits. For further calculations, it is suggested to use the equation F=ilB without including the sine of the angle, as the current and magnetic field are perpendicular. The alternative approach of calculating the magnetic field using B = μo*I/(2*π*r) is also mentioned, emphasizing the relationship between the currents in both wires.
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Homework Statement



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Homework Equations



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The Attempt at a Solution



Is this the correct equation to find the current (I)? I setup a free body diagram for bar 2,

TCos(24)-(.036kg)(9.8m/s^2)=0 (for y)
-TSin(24)+ (Eqtn for force between two parallel wires but with the current squared) (for x)

Then I solved for I, which I got 594A. Once I get I, do I use F=ilBsin(24) for part C? Or do I use the equation for force between two wires but with only I (not I^2)?
 
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Your 594 A looks good. I got 596 but wasn't very careful with significant digits. You could use F=ilB but I don't think you want a sin(24) in it. The current and the magnetic field are perpendicular to each other. Or you could use B = μo*I/(2*π*r) since you know the I is the same in the other wire.
 
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