Forces on adjacent accelerating bodies

AI Thread Summary
The problem involves calculating the acceleration of two bodies, A and B, when they are attached and subjected to the same force. Body A has an acceleration of 0.640 m/s², leading to a calculated mass of 1.5625 kg. The next step is to determine the mass of Body B using its acceleration of 0.359 m/s². Once both masses are known, the combined mass can be used to find the acceleration when the same force is applied to both bodies together. The discussion emphasizes the importance of correctly calculating the masses to solve the problem accurately.
subzero800
Messages
3
Reaction score
0

Homework Statement



The same force that gives the standard 1 kg mass an acceleration of 1.00 m/s2 acts first on body A, producing an acceleration of 0.640 m/s2, and then on body B, producing an acceleration of 0.359 m/s2. Find the acceleration produced when A and B are attached and the same force is applied.



Homework Equations



ƩF=ma

The Attempt at a Solution



I started by trying to figure out the mass of body a by doing 1 N/.640 m/s2 and I have 1.5625 Kg for Body A--I'm not sure if this is correct nor how to complete the problem.
 
Physics news on Phys.org
subzero800 said:
I started by trying to figure out the mass of body a by doing 1 N/.640 m/s2 and I have 1.5625 Kg for Body A--I'm not sure if this is correct nor how to complete the problem.
So far, so good. You found the mass of body A. Now find the mass of Body B.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Newton's law problem: Pushing 2 stacked blocks on a horizontal table
Replies
13
Views
3K
Find the acceleration of the system (2 blocks sliding on a table)
Replies
23
Views
2K
A misconception I have about impulse formula interpretation
Replies
2
Views
2K
F = ma for a lift (elevator) carrying passengers
Replies
5
Views
2K
Newton's Third Law: Acceleration of box and worker
Replies
2
Views
5K
with this tension problem -- Mass on an accelerating cable
Replies
3
Views
2K
Center of mass and momentum- A question about systems
Replies
25
Views
1K
How Does Friction Affect Acceleration on an Incline?
Replies
19
Views
3K
Unraveling the Mystery of Mass & Force: A 180 lb Person
Replies
3
Views
2K
Understanding Acceleration and Center of Mass in Shock Absorption
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top