Formula for determining if one vector is a multiple for two others

Click For Summary

Homework Help Overview

The discussion revolves around determining if one vector can be expressed as a linear combination of two other vectors. The original poster presents an equation involving two vectors and seeks a method to find coefficients that satisfy this equation.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for finding coefficients, including substitution and comparing vector components. There is mention of Gaussian elimination as an attempted approach, and some participants question how the original equation was derived.

Discussion Status

The conversation includes attempts to clarify the process of finding the coefficients and explores different interpretations of the problem. Some participants provide insights into the structure of the equations that arise from comparing vector components.

Contextual Notes

There is a reference to the original poster's confusion regarding the orientation of the vectors during Gaussian elimination, which may have impacted their results. The discussion does not reach a consensus on a single method but explores multiple avenues for understanding the problem.

robertjford80
Messages
388
Reaction score
0

Homework Statement



Screenshot2012-05-13at111042AM.png

Screenshot2012-05-13at111113AM.png



The Attempt at a Solution



Is there a formula for determining

x = 3v1 - 2v2

It looks like you just have to do trial and error. I tried Gaussian Elimination on the two vectors and got -1.5 and .5 so that didn't work.
 
Physics news on Phys.org
Do you mean, how to find a1 and a2? Just substitute the given vectors and solve.
 
Quite simply, by comparing the three components of the vector on each side of the equation, the following things must be true:
[tex]x^1 = a_1 v^1_1 + a_2 v^1_2[/tex]
[tex]x^2 = a_1 v^2_1 + a_2 v^2_2[/tex]
[tex]x^3 = a_1 v^3_1 + a_2 v^3_2[/tex]
where the superscript denotes the first, second or third element of the vector. This leads to the set of equations
[tex]-1 = a_1 + 2 a_2[/tex]
[tex]-3 = -a_1[/tex]
[tex]4 = 2a_1 + a_2[/tex]
From there it should be obvious how that solution was obtained.
 
I mean how they found out that 3 times vector 1 - 2 times vector 2 = x = (-1,-3,4)
 
Steely Dan, thanks, I got it.

when i did gaussian elimination i wrote the vector horizontally rather than vertically, that's why I was wrong.
 

Similar threads

Replies
29
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 18 ·
Replies
18
Views
6K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K