Formula for determining if one vector is a multiple for two others

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robertjford80
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Homework Statement



Screenshot2012-05-13at111042AM.png

Screenshot2012-05-13at111113AM.png



The Attempt at a Solution



Is there a formula for determining

x = 3v1 - 2v2

It looks like you just have to do trial and error. I tried Gaussian Elimination on the two vectors and got -1.5 and .5 so that didn't work.
 
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Do you mean, how to find a1 and a2? Just substitute the given vectors and solve.
 
Quite simply, by comparing the three components of the vector on each side of the equation, the following things must be true:
[tex]x^1 = a_1 v^1_1 + a_2 v^1_2[/tex]
[tex]x^2 = a_1 v^2_1 + a_2 v^2_2[/tex]
[tex]x^3 = a_1 v^3_1 + a_2 v^3_2[/tex]
where the superscript denotes the first, second or third element of the vector. This leads to the set of equations
[tex]-1 = a_1 + 2 a_2[/tex]
[tex]-3 = -a_1[/tex]
[tex]4 = 2a_1 + a_2[/tex]
From there it should be obvious how that solution was obtained.
 
I mean how they found out that 3 times vector 1 - 2 times vector 2 = x = (-1,-3,4)
 
Steely Dan, thanks, I got it.

when i did gaussian elimination i wrote the vector horizontally rather than vertically, that's why I was wrong.