Formula for gravity/circular motion in terms of V? (i think )

AI Thread Summary
The discussion focuses on deriving the formula for gravity and circular motion in terms of velocity (V). It establishes the relationship between gravitational force (Fg) and centripetal force (Fc) using the equations F=mg and Fc=mv²/r. By substituting these equations, the participants clarify that when simplifying, the mass of the orbiting object cancels out, leaving the mass of the Earth in the final equation. This leads to the conclusion that the centripetal force is based on the gravitational pull from the Earth. The conversation emphasizes understanding which mass is relevant in the context of circular motion and gravitational force.
tman12345
Messages
3
Reaction score
0
If F=mg, and Fc=Fg, Fc=mv2/r (thats v squared; my apologies, i have no idea how to use the superscript button), and Fg=Gm(1)m(2)/r2 (squared), where m(2) is the mass of, say, the earth, and m(1) is the mass of the object orbiting the earth. By substituting these equations together, we get

mv2/r=Gm(1)m(2)/r2,

and we can cancel out the r on the left, and the m (which is mass). but I have a problem; which mass is canceled out on the right side? is it the mass of the object or mass of the earth?


thanks
 
Physics news on Phys.org
Which do you think? Which mass is executing circular motion as it orbits the other? Which mass are you finding the centripetal force on?
 
I think i am supposed to be finding it with respect to the earth, so I believe then the mass of the Earth is what is left
 
tman12345 said:
I think i am supposed to be finding it with respect to the earth, so I believe then the mass of the Earth is what is left
Right.

Force on orbiting object due to gravity: F = GM_{earth}M_{object}/R^2

Applying Newton's 2nd law to orbiting object: F = M_{object}V_{object}^2/R

Combined:

M_{object}V_{object}^2/R = GM_{earth}M_{object}/R^2

V_{object}^2/R = GM_{earth}/R^2
 
Cancel out mass of object in revolution,thats the mass acted upon by the centripetal force.
 
thanks a lot! that really helped.
next time ill try to not leave my physics book at school over the weekend
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Let there be a person in a not yet optimally designed sled at h meters in height. Let this sled free fall but user can steer by tilting their body weight in the sled or by optimal sled shape design point it in some horizontal direction where it is wanted to go - in any horizontal direction but once picked fixed. How to calculate horizontal distance d achievable as function of height h. Thus what is f(h) = d. Put another way, imagine a helicopter rises to a height h, but then shuts off all...
Back
Top