Is This the Best Formula for Calculating Work and Time?

AI Thread Summary
The discussion centers on the formula for calculating work and time, particularly in scenarios involving multiple workers. The proposed formula, N1 * D1 * W1 = N2 * D2 * W2, is debated, with emphasis on understanding the rate of work per person. An example illustrates how to calculate total work using the rate of work, showing that the rate can be omitted in certain calculations. The conversation highlights the simplicity of these problems, comparing them to basic mathematical principles. Ultimately, the formula's effectiveness in solving practical work problems is affirmed.
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Hi,

whats the formula for work and Time ?


is it this ?

N1 * D1 * W1 =N2*D2*W2

where ,
N1=No of Persons
D1=No of days
W1=work


N2=No of Persons
D2=No of days
W2=work


is that's formula correct for work and time ?
 
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The simplest formula for mechanical work (in Physics) is
W = F s
Here, the force is contant and parallel to displacement and the body moves in a steady direction. W is work, F is force and s is displacement. The result is in Joules.

Unless you want manhours? What exactly are you trying to do? :)
 
no...there is no physics involved in it.

i'm talking about maths.

problems like..."20 man works for 10 days did a work, how long it would be taken by 30 man"?

this kind of problem

whats the formula ?

I have forgotten the formula...is it like same as i posted ?
 
N_1 R D_1 = W = N_2 R D_2

Where: N = number of men; R = rate of work done per man (assumed constant); D = days (or time); W = total work done.
 
>R = rate of work done per man (assumed constant);

what does it mean ?

can you give an example of it ?

thank you
 
Don't treat this as some esoteric formula from the ancients. It should be just "common sense", a variation of "Distance = Rate X time".

An example of R would be: a man can lift 50 bales of hay per day, so R = 50 bales/day/man.

So, if one man can lift 50 per day, how much total can be lifted in 3 days by 5 men?

Using W = N R D gives, W(total) = (5 men) (50 bales/day/man) (3 days) = 750 bales

But to solve a problem like " if 20 men working 10 days did a certain amount of work, how long would it take 30 men to do the same work?" you don't have to know R. Just use:

N_1 R D_1 = W = N_2 R D_2
(20)(R)(10) = (30)(R)(D_2)

Note that the Rs just drop out, and D_2 = 20/3 days.
 
Those are the dumbest of word problems. I would be tempted to answer : "The job would never get done, because the extra men would entice the entire lot to unionise and strike for better pay and conditions".
 
this is correct
N1 * D1 * W2 =N2*D2*W1
where ,
N1=No of Persons
D1=No of days
W1=work


N2=No of Persons
D2=No of days
W2=work
 
Except that just "work" is meaningless. I prefer Doc Al's "rate of work per day per man".
 
  • #10
yes bro u r right for "work" explanation but except tht mine formula is best one
 
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