Forward vs Reverse Reaction (both endo/exo thermic)

  • Thread starter Thread starter ldv1452
  • Start date Start date
  • Tags Tags
    Reaction Reverse
AI Thread Summary
Both the forward and reverse reactions cannot be simultaneously exothermic or endothermic due to the principle of energy conservation. Enthalpy (H) is a state function, meaning it is independent of the process path taken. The enthalpy change in any reaction is defined by the equation H_final - H_initial = ΔH. Therefore, if a forward reaction has a negative enthalpy change (exothermic), the reverse reaction will have a positive change of equal magnitude. This relationship can be expressed as H_forward = -H_reverse.
ldv1452
Messages
69
Reaction score
0
Can both the forward and reverse reaction be endothermic or exothermic? Or must they ALWAYS be inverse one another?

Thanks
 
Chemistry news on Phys.org
What about energy conservation?
 
They cannot both be exothermic or endothermic. Enthalpy (H) is a state function. This means that the enthalpy of a system is completely independent of how one arrived at that system. It's like mass. It follows from this that the enthalpy change in any process is expressed by:

H_{final}-H_{initial} = \Delta\ H

for all processes. So if the forward process has a negative change in enthalpy (exothermic), the reverse process will have a positive change in enthalpy of equal magnitude. For a reverse reaction, you just switch the "final" and "initial" states, which amounts to multiplying the left by negative one. So this equation relates forward and reverse processes:

H_{for}= -H_{rev}

EDIT:
Sorry I can't get LaTex to work right, I'm new to this.
 
Last edited:
horsecandy911 said:
They cannot both be exothermic or endothermic. Enthalpy (H) is a state function. This means that the enthalpy of a system is completely independent of how one arrived at that system. It's like mass. It follows from this that the enthalpy change in any process is expressed by:

H_{final}-H_{initial} = \Delta\ H

for all processes. So if the forward process has a negative change in enthalpy (exothermic), the reverse process will have a positive change in enthalpy of equal magnitude. For a reverse reaction, you just switch the "final" and "initial" states, which amounts to multiplying the left by negative one. So this equation relates forward and reverse processes:

H_{for}= -H_{rev}

Good answer on this. I appreciate it. Thanks!
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!

Similar threads

Back
Top