Forward vs Reverse Reaction (both endo/exo thermic)

  • Thread starter Thread starter ldv1452
  • Start date Start date
  • Tags Tags
    Reaction Reverse
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 12K views
ldv1452
Messages
69
Reaction score
0
Can both the forward and reverse reaction be endothermic or exothermic? Or must they ALWAYS be inverse one another?

Thanks
 
Chemistry news on Phys.org
They cannot both be exothermic or endothermic. Enthalpy (H) is a state function. This means that the enthalpy of a system is completely independent of how one arrived at that system. It's like mass. It follows from this that the enthalpy change in any process is expressed by:

[tex]H_{final}-H_{initial} = \Delta\ H[/tex]

for all processes. So if the forward process has a negative change in enthalpy (exothermic), the reverse process will have a positive change in enthalpy of equal magnitude. For a reverse reaction, you just switch the "final" and "initial" states, which amounts to multiplying the left by negative one. So this equation relates forward and reverse processes:

[tex]H_{for}= -H_{rev}[/tex]

EDIT:
Sorry I can't get LaTex to work right, I'm new to this.
 
Last edited:
horsecandy911 said:
They cannot both be exothermic or endothermic. Enthalpy (H) is a state function. This means that the enthalpy of a system is completely independent of how one arrived at that system. It's like mass. It follows from this that the enthalpy change in any process is expressed by:

[tex]H_{final}-H_{initial} = \Delta\ H[/tex]

for all processes. So if the forward process has a negative change in enthalpy (exothermic), the reverse process will have a positive change in enthalpy of equal magnitude. For a reverse reaction, you just switch the "final" and "initial" states, which amounts to multiplying the left by negative one. So this equation relates forward and reverse processes:

[tex]H_{for}= -H_{rev}[/tex]

Good answer on this. I appreciate it. Thanks!