Fourier Expansion in 3D: Expansion of V(r)

Logarythmic
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I'm used to use

\tilde{f} (x) = a_n|e_n>

where

|e_n> = e^{2 \pi inx / L}

and

a_n = \frac{1}{L}<e_n|f>

for my Fourier expansions.

How do I expand a function in 3 dimensions, for example

V(\vec{r}) = \frac{e^{-\lambda r}}{r}

?
 
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There is still just one variable in there, no?
 
---I deleted this, it's mostly nonsense and it does't apply to the problem.---

But in my opinion, mathematically, it makes no difference if you have an r or an x in there; just do the Fourier expansion btw r_0 and r_1 as you would a fct of x.
 
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Logarythmic said:
I'm used to use

\tilde{f} (x) = a_n|e_n>

where

|e_n> = e^{2 \pi inx / L}

and

a_n = \frac{1}{L}<e_n|f>

for my Fourier expansions.

How do I expand a function in 3 dimensions, for example

V(\vec{r}) = \frac{e^{-\lambda r}}{r}

?
The basis functions are products whose factors are the 1-D functions in x, y, and z.
 
So |e_n> = e^{2 \pi in \vec{r} /L} = e^{2 \pi in x /L} e^{2 \pi in y /L} e^{2 \pi in z /L} and r = \sqrt{x^2 + y^2 + z^2}?
 
Yes for the last product on the right and the r; the Ls could be different for each dimension.

|e_n> = e^{2 \pi in x /L_x} e^{2 \pi in y /L_y} e^{2 \pi in z /L_z}
 
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So to expand V(\vec{r}) I have to rewrite it in terms of x, y ,z or does quasar987 have a point there?
 
Logarythmic said:
So to expand V(\vec{r}) I have to rewrite it in terms of x, y ,z or does quasar987 have a point there?
I thought you wanted the expansion for any function in 3-D. If the function is only a function of r, then you could do a 1-D expansion in r. There are other orthogonal functions that are often used in 3-D in cylindrical or spherical coordinates.
 
Yes, first of all I want to solve this problem but I also want to learn something from it. ;)
 
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