Fourier Intergrals and transforms

  • Context: Undergrad 
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Discussion Overview

The discussion revolves around the evaluation of a Fourier integral, specifically the integral defined as F(ω) = (1/√(2π)) ∫ dte^(-αt)cos(ωt). Participants explore methods for solving this integral and express curiosity about the nature and complexity of Fourier integrals.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant expresses uncertainty about how to evaluate the Fourier integral and questions its purpose.
  • Another participant suggests using integration by parts as a method to approach the integral.
  • A third participant proposes a substitution involving the exponential form of the cosine function, indicating that this could simplify the integral into a sum of two exponential integrals.
  • A later reply indicates familiarity with the integral but notes that the substitution method had not been considered previously, expressing surprise at the perceived simplicity of the Fourier integral.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best method for evaluating the integral, and there is a mix of familiarity and confusion regarding the concept of Fourier integrals.

Contextual Notes

Some participants acknowledge limitations in their understanding of the integral's complexity and the methods available for its evaluation.

Brewer
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How do I do a Fourier integral (and what's the point of them??)

I've been asked to evaluate

[tex]F(\omega) = \frac{1}{\sqrt{2\pi}}\int dte^{-\alpha t}cos\omega t[/tex]

and I've not the foggiest idea what to do. I thought I could just go about doing in the integral by parts (limits are 0 and infinity by the way), but on further research I don't think I can do that can I?
 
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Try integration by parts.
 
cos(u)=(exp(iu)+exp(-iu))/2

Substitute into your integral and you will have the sum of two exp integrals. I presume you can do that.
 
Yes that's familliar. I have done this integral before - just never dawned on me to use the substitution.

I was also a little confused when it called it a Fourier Integral. I thought it was going to be a lot more complex than it appears to be now.
 

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