Fourier transform

  • Thread starter kolycholy
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  • #1
kolycholy
39
0
how can I find Fourier transform of 1/(1+4t^2)?
hmmm =/
 

Answers and Replies

  • #2
moe_3_moe
72
0
try to take x=2t and use the symmetry or duality property and then the scaling property
 
  • #3
antoker
84
0
Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]
 
Last edited:
  • #4
Manchot
473
4
Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]
You've mixed up differentiation and integration...
 
  • #5
moe_3_moe
72
0
manchot is right ... so complicated ... i think the properties of the Fourier transformation is better
 
  • #6
antoker
84
0
damn... you're right ;)
 
  • #7
kolycholy
39
0
i tried taking a look at the Fourier transform properties..
but hmm, still confused
 
  • #8
moe_3_moe
72
0
check the scaling and the symmetry property ... sorry i can't tell the answer ... it is the rules ...
 

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