- #1

- 39

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how can I find fourier transform of 1/(1+4t^2)?

hmmm =/

hmmm =/

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- Thread starter kolycholy
- Start date

- #1

- 39

- 0

how can I find fourier transform of 1/(1+4t^2)?

hmmm =/

hmmm =/

- #2

- 72

- 0

try to take x=2t and use the symmetry or duality property and then the scaling property

- #3

- 84

- 0

Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]

Last edited:

- #4

- 469

- 4

You've mixed up differentiation and integration...Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]

- #5

- 72

- 0

- #6

- 84

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damn.... you're right ;)

- #7

- 39

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i tried taking a look at the fourier transform properties..

but hmm, still confused

but hmm, still confused

- #8

- 72

- 0

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