Fourier transform

  • Thread starter kolycholy
  • Start date
  • #1
39
0
how can I find fourier transform of 1/(1+4t^2)?
hmmm =/
 

Answers and Replies

  • #2
72
0
try to take x=2t and use the symmetry or duality property and then the scaling property
 
  • #3
84
0
Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]
 
Last edited:
  • #4
468
4
Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]
You've mixed up differentiation and integration...
 
  • #5
72
0
manchot is right ... so complicated ... i think the properties of the fourier transformation is better
 
  • #6
84
0
damn.... you're right ;)
 
  • #7
39
0
i tried taking a look at the fourier transform properties..
but hmm, still confused
 
  • #8
72
0
check the scaling and the symmetry property ... sorry i can't tell the answer ... it is the rules ...
 

Related Threads on Fourier transform

Replies
7
Views
3K
Replies
6
Views
17K
  • Last Post
Replies
9
Views
24K
  • Last Post
Replies
6
Views
3K
  • Last Post
Replies
6
Views
5K
  • Last Post
Replies
18
Views
7K
Replies
4
Views
6K
  • Last Post
Replies
3
Views
1K
Replies
19
Views
3K
Replies
1
Views
4K
Top