Fourier transform

kolycholy · Apr 4, 2007

how can I find fourier transform of 1/(1+4t^2)?
hmmm =/

moe_3_moe · Apr 4, 2007

try to take x=2t and use the symmetry or duality property and then the scaling property

antoker · Apr 4, 2007

Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]

Manchot · Apr 4, 2007

antoker said: ↑

Use the fact that your expression can be expressed as [tex]\int{\frac{f(t)}{g(t)}dx}[/tex], where [tex]f(t) = e^{-j\omega t}, g(t)=1+4t^{2}[/tex] and proceed as stated by the rule. If i remember it correctly it goes something like [tex]\frac{f'(t)g(t)-g'(t)f(t)}{g(t)^{2}}[/tex]

You've mixed up differentiation and integration...

moe_3_moe · Apr 4, 2007

manchot is right ... so complicated ... i think the properties of the fourier transformation is better

antoker · Apr 4, 2007

damn.... you're right ;)

kolycholy · Apr 4, 2007

i tried taking a look at the fourier transform properties..
but hmm, still confused

moe_3_moe · Apr 5, 2007

check the scaling and the symmetry property ... sorry i can't tell the answer ... it is the rules ...