Snoopey
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Homework Statement
I've been given the following function:
g(x) = \frac{\gamma}{2}e^{-\gamma \left|x\right|} with \gamma>0
First thing I needed to do was to prove \int^{-\infty}_{\infty}g(x)dx=1 which was simple enough.
I hit a problem when trying to find the Fourier transform \widetilde{g}(k) of g(x)
I'm asked to show the transform is of the form
\widetilde{g}(k)=a\frac{1}{1+\frac{k^{2}}{s^{2}}}
and find a and s
Homework Equations
\widetilde{g}(k) = \frac{1}{\sqrt{2\pi}}\int^{-\infty}_{\infty}e^{-ikx}g(x)dx
The Attempt at a Solution
I try to perform integration by parts on
\widetilde{g}(k) = \frac{1}{\sqrt{2\pi}}\int^{-\infty}_{\infty}e^{-ikx}\frac{\gamma}{2}e^{-\gamma \left|x\right|}dx
but whenever I try this I end up with uv equalling vdu so the whole expression turns out as zero. I think this is probably because I don't really know what I'm doing with the integration with those limits to infinity. I can split up g(x) because its an even function but not the e^{-ikx} part.
I've plugged this into wolfram alpha and it churned out a = \frac{1}{2\pi} and s = \gamma, I'm just not sure how to get there.
Any help appreciated!