Fraction Simplification of Impedances and Resistances

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To simplify the transfer function H(jw) = ZL/(R + ZL), where ZL is the impedance of an inductor and R is the resistance, one approach is to express it as ZL(1/R + 1). However, a concern arises regarding the units, as the first term is dimensionless while the second has units of ohms. A user suggests breaking down the expression 2.2e3/(2.2e3 + i2π10e-3) into simpler terms, indicating a need for clarity in handling complex impedances. The discussion also highlights that the expression can be represented as i*2π*f*L/(R + i*2π*f*L), focusing on frequency-dependent reactance. Overall, the thread emphasizes the importance of understanding impedance and transfer functions in electrical engineering.
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My algebra is really rusty, anyway I'm trying to simplify a Transfer Function so I have

H(jw)=ZL/R+ZL so ZL is the impedance of an inductor and R is the impedance of the Resistor, my question is how would I go about simplifying that transfer function into it's simplest form?

Thanks,

Jordan
 
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Well you could do ZL/R+ZL = ZL(1/R + 1) if that is a help.
But there is something odd about ZL/R+ZL. The first term has no units while the second has units of ohms.

I don't know what a "transfer function" is so I'm not much help!
 
Let me throw another one out there to hopefully make it easier to understand (don't worry about the transfer function)

so 2.2e3/2.2e3+i2pi10e-3

How would that be simplified or in simpler terms

a/a+b

How would you simplify that

The problem above would be i*2pi*f*L/R+i*2pi*f*L

f is the frequency and 2pi*f would give us the reactance of the Inductor so I'm trying to figure out how to simplify everything.
 
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