Fraction Simplification of Impedances and Resistances

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SUMMARY

The discussion focuses on simplifying transfer functions involving impedances, specifically the expression H(jw) = ZL/(R + ZL), where ZL represents the impedance of an inductor and R is the resistance. A participant suggests rewriting the expression as ZL(1/R + 1) for simplification. The conversation also touches on the units of the terms involved, highlighting the need for consistent units in electrical equations. Additionally, the simplification of the expression 2.2e3/(2.2e3 + i2π10e-3) is explored, emphasizing the role of frequency in determining reactance.

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Jordash
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My algebra is really rusty, anyway I'm trying to simplify a Transfer Function so I have

H(jw)=ZL/R+ZL so ZL is the impedance of an inductor and R is the impedance of the Resistor, my question is how would I go about simplifying that transfer function into it's simplest form?

Thanks,

Jordan
 
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Well you could do ZL/R+ZL = ZL(1/R + 1) if that is a help.
But there is something odd about ZL/R+ZL. The first term has no units while the second has units of ohms.

I don't know what a "transfer function" is so I'm not much help!
 
Let me throw another one out there to hopefully make it easier to understand (don't worry about the transfer function)

so 2.2e3/2.2e3+i2pi10e-3

How would that be simplified or in simpler terms

a/a+b

How would you simplify that

The problem above would be i*2pi*f*L/R+i*2pi*f*L

f is the frequency and 2pi*f would give us the reactance of the Inductor so I'm trying to figure out how to simplify everything.
 

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