Franklin's lightning bells. Easy Question.

  • Thread starter Thread starter shimizua
  • Start date Start date
  • Tags Tags
    bells Lightning
AI Thread Summary
In the Franklin's lightning bells experiment, if the left bell is insulated and not grounded, it will not gain electrons when the right bell is struck by lightning. Consequently, the negative charges from the ball will not transfer to the left bell, leaving it without a charge. The ball will remain negatively charged due to the lack of grounding for the left bell. The overall effect is that the left bell remains unaffected while the right bell continues to attract positive charges. This scenario highlights the importance of grounding in electrical experiments.
shimizua
Messages
99
Reaction score
0
Franklin's lightning bells. Easy Question. Please Help!

Homework Statement


Assume (for this part only) that the metal bell on the left was not grounded but connected to an insulator. Describe the changes as compared to question 4.
So the franklin lighting bells experiment has a bell on the right attached to a lightning rod, a metal ball on the left of it and then on the left of the ball is another metal bell that is attached to a metal pole leading to the ground.
I know that when the bell on the right is struck by lightning the negative charges are transferred to the bell and then attracts the positive charges from the ball which transfers negative charges to the ball that then move to the bell on the right and transfers negative charges to the bell on the right and the electrons flow to the ground.
So now with an insulator around the pole for the bell that leads to the ground what would happen. I believe that the bell would not gain any electrons and the ball would stay negatively charged. just wanted to check though.
 
Physics news on Phys.org
Homework Equations N/AThe Attempt at a SolutionYes, that is correct. Without the metal pole attached to the bell on the left and leading to the ground, the bell would not receive any electrons and the ball would remain negatively charged.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...

Similar threads

Back
Top