Free-body diagram velocity vector

AI Thread Summary
The discussion centers on a free-body diagram of a particle on a tilted plane, where the resulting force is directed along the negative x-axis. There is a debate about the possibility of a velocity vector pointing in the positive direction, highlighting that net force indicates acceleration rather than velocity. Participants clarify that free-body diagrams exclusively depict forces and moments, not velocity or acceleration vectors. For a comprehensive understanding, supplemental diagrams may be necessary to illustrate velocity. The conversation emphasizes the distinction between forces and motion in physics.
alingy1
Messages
325
Reaction score
0
My teacher gave me a solved problem to practice. There is a free-body diagram of a particle on a tilted plane. The resulting force points in the direction of the negative x-axis, aligned with the inclination of the plane.Am I the only one that thinks there could also be a velocity vector pointing in the positive direction? After all, the net force only represents acceleration.
 
Last edited:
Physics news on Phys.org
It would be a lot easy if you upload the free-body diagram of that plane, so we can really help you.
 
Free Body Diagrams show only the forces and moments (torques) acting on the system or parts of the system. They do not show velocity or acceleration vectors, which, if needed for clarity,, may be shown in a supplemental
diagram or at least apart from the free body diagram itself.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top