1. A flower pot falls out of a window and past the window below (ignore air resistance). It takes the post .42 s to pass this window, which is 1.9m high. How far is the top of the window below the windowsill from which the flowerpot fell? answer: .31 m 2. v = v0 + at x = x0 + v0t + 1/2at^2 v^2 = v0^2 + 2a(x - x0) 3. The attempt at a solution Known facts: t = .42 s bottom window height = 1.8 a = -g x0 = 0 (if the origin is the top windowsill) v0 = ? x = ? x = 0 + v0(.42) + 1/2(-9.8)(.42)^2 So I need to find the initial velocity so I can get the total distance and subtract it from the 1.9. If I had the total distance down, then I could get it easy, but I'm stumped from here since I'm trying to find the total distance. I've tried using v0=0 and that didn't work. I also tried setting the v = 0 (thinking I could do that sense the problem ends with that bottom window). Every route I go it seems I'm still left with two unknowns or I end with a total distance of .86 which isn't even longer than the bottom window. Any hints on which equations to put together?