Frequency and Length: Solving for String Length

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Homework Help Overview

The discussion revolves around the relationship between frequency and string length in the context of vibrating strings, specifically focusing on the first harmonic and its implications for calculating string length based on frequency changes.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the calculation of string length based on known frequency and wavelength, questioning the specific lengths being referred to in the context of the problem.

Discussion Status

The discussion is active, with participants providing insights into the mechanics of string vibration and clarifying which parts of the string are involved in producing sound. There is an ongoing exploration of the assumptions regarding string length and vibration points.

Contextual Notes

Participants are discussing the implications of holding the string at different points and how that affects the vibrating length, as well as the potential sound output based on the method of playing the instrument.

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Homework Statement


upload_2015-9-23_20-54-40.png


Homework Equations

The Attempt at a Solution


for the first harmonic, the wavelength is twice the length of string.
so 0.296m x 2 = 0.592m is the wavelength

with the wavelength and frequency known, we solve for v in v = ƒλ

v = 0.592m x 440 Hz = 260 m/s

then to solve for the length of new string , we just use the same v (260 m/s) and use the new frequency (523 Hz) and solve for the L?

if so , I got 24.9 cm
 
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goonking said:

Homework Statement


View attachment 89239

Homework Equations

The Attempt at a Solution


for the first harmonic, the wavelength is twice the length of string.
so 0.296m x 2 = 0.592m is the wavelength

with the wavelength and frequency known, we solve for v in v = ƒλ

v = 0.592m x 440 Hz = 260 m/s

then to solve for the length of new string , we just use the same v (260 m/s) and use the new frequency (523 Hz) and solve for the L?

if so , I got 24.9 cm
With regard to the parts of the string, what length have you calculated as 24.9cm? What length does it ask for?
 
haruspex said:
With regard to the parts of the string, what length have you calculated as 24.9cm? What length does it ask for?
i calculated the length starting from beneath the finger to the nut to be 24.9 cm
 
goonking said:
i calculated the length starting from beneath the finger to the nut to be 24.9 cm
What part of the string is vibrating at 523Hz?
 
haruspex said:
What part of the string is vibrating at 523Hz?
just the 24.9 cm of string between the finger and nut I suppose since the rest isn't vibrating
 
goonking said:
just the 24.9 cm of string between the finger and nut I suppose since the rest isn't vibrating
What is being used to make the string vibrate? What part of the string is it acting on?
 
haruspex said:
What is being used to make the string vibrate? What part of the string is it acting on?
to make the string vibrate, you would have to pluck it, and if you held the string down with your thumb, only the part of the string between your thumb and the nut, will vibrate.
 
goonking said:
to make the string vibrate, you would have to pluck it, and if you held the string down with your thumb, only the part of the string between your thumb and the nut, will vibrate.
You could do that, but you would get hardly any sound out of the violin. Whether played with a bow (as in the diagram) or plucked, it is the part between the bridge and the finger that is plucked or bowed. (The vibration is transferred through the bridge to the broad wooden lamina, and thence to the air inside.)
 
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haruspex said:
You could do that, but you would get hardly any sound out of the violin. Whether played with a bow (as in the diagram) or plucked, it is the part between the bridge and the finger that is plucked or bowed. (The vibration is transferred through the bridge to the broad wooden lamina, and thence to the air inside.)
ah, I had to subtract the two, 29.6 cm - 24.9 cm = 4.7 cm.
 
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goonking said:
ah, I had to subtract the two, 29.6 cm - 24.9 cm = 4.7 cm.
Yes.
 

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