With regard to the parts of the string, what length have you calculated as 24.9cm? What length does it ask for?goonking said:
i calculated the length starting from beneath the finger to the nut to be 24.9 cmharuspex said:
What part of the string is vibrating at 523Hz?goonking said:
just the 24.9 cm of string between the finger and nut I suppose since the rest isn't vibratingharuspex said:
What is being used to make the string vibrate? What part of the string is it acting on?goonking said:
to make the string vibrate, you would have to pluck it, and if you held the string down with your thumb, only the part of the string between your thumb and the nut, will vibrate.haruspex said:
You could do that, but you would get hardly any sound out of the violin. Whether played with a bow (as in the diagram) or plucked, it is the part between the bridge and the finger that is plucked or bowed. (The vibration is transferred through the bridge to the broad wooden lamina, and thence to the air inside.)goonking said:
ah, I had to subtract the two, 29.6 cm - 24.9 cm = 4.7 cm.haruspex said:
Yes.goonking said:
The frequency of a vibrating string is inversely proportional to its length. This means that as the length of the string increases, the frequency decreases and vice versa.
The string length can be measured using a ruler or measuring tape. It is typically measured from the fixed end of the string to the point where it is attached to a movable object, such as a tuning peg or finger.
Understanding this relationship is crucial in many scientific fields, such as acoustics and music. It allows us to calculate the frequency of a string and predict how changing the length of the string will affect its pitch.
The tension of a string is directly proportional to its frequency. This means that as the tension increases, the frequency also increases. However, the tension does not affect the length of the string.
Yes, the frequency of a string can be changed by altering the tension. This can be done by tightening or loosening the string, which will affect its frequency without changing its length.