I found weight that measured 2 lbs, hung it off the end of the wire which compressed the spring on the other end, and then crimped and cut the wire at that length.nasu said:
The formula for calculating the frequency of a wire/spring system is:
f = 1 / (2π) * √(k/m)
Where f is the frequency, k is the spring constant, and m is the mass of the object attached to the spring.
The length of the wire/spring has a direct effect on the frequency. As the length increases, the frequency decreases and vice versa. This relationship is described by the formula:
f = 1 / (2π) * √(k/m) * (1/L)
Where L is the length of the wire/spring.
The spring constant is a measure of the stiffness of the spring. It determines how much force is required to stretch or compress the spring. A higher spring constant results in a higher frequency, while a lower spring constant results in a lower frequency.
The mass of the object attached to the spring also affects the frequency. A heavier mass will result in a lower frequency, while a lighter mass will result in a higher frequency. This relationship is described by the formula:
f = 1 / (2π) * √(k/m)
Yes, the frequency of a wire/spring system can be changed by altering the length, spring constant, or mass of the object attached to the spring. Additionally, the frequency can also be changed by introducing a damping force, which reduces the amplitude of the oscillations and thus changes the frequency.