Frequency of G 3 Octaves Up on Middle Ages Harp - 200 Hz

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A middle ages harp produces a low A at 200 Hz, and the discussion revolves around calculating the frequency of G three octaves higher. The correct approach involves recognizing that G is 10 semitones above A, leading to a calculation of 2^(10/12) multiplied by the frequency of A. The confusion arises from the interpretation of octaves and semitones, with clarification needed on whether to count from A or to adjust for the whole tone. Ultimately, the correct frequency for G three octaves up from the low A is determined through careful consideration of the semitone structure in music theory.
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A harp from the middle ages produces a low A with a frequency of 200 Hz. What is the frequency of G on the same harp 3 octaves up?



frequency=2^(m/12)*frequency


SO 2^(m/12)*200Hz, I decided that m=9 and for each increase in an octave I though that you were supposed to mutliply 12 so in this case it would 12*12*12. The equation will read
2^(9/36)*200=237.8Hz but this is the wrong answer.
Here is the hint that is provided: Remember the order of the notes is A, A#, B, C, C#, D, D#, E, F, F#, G, G# (m=0,1,2,3,4,5,6,7,8,9,10,11,12).

I think I am just using the wrong numbers but any help would be great!
 
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I think they mean the G that is 3 octaves minus a whole tone above A. (it's slightly ambiguous, they could also mean 3 octaves + 10 semitones, but I took the G that was closest to the A that's 3 octaves up)

you can just count how many semitones there are between the Low A and this G, or you can find out the frequency of the G that's 2 semitones below the low A and then move up 3 octaves

An octave is 12 semitones so m = 12. that means the frequecy of a
note that's one octave up is a factor 2^(12/12) = 2 higher.
 
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