Frequency of oscillation (in Hz) question help Thanks

AI Thread Summary
A 320 kg wooden raft experiences a 3.5 cm deeper immersion when a 75 kg man steps on it, leading to oscillation after he steps off. The force constant was calculated to be 21,000 Nm, which is confirmed as correct. The frequency of oscillation is derived using the formula f = 1/(2π)√(k/m), where k is the force constant and m is the mass of the raft. Substituting the values, the calculated frequency is approximately 0.776 Hz. The discussion emphasizes treating the raft as a mass-spring system to analyze the oscillation behavior.
nukeman
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Homework Statement



A 320 kg wooden raft floats on a lake in equilibrium. When a 75 kg man steps carefully onto the raft, it floats 3.5 cm deeper into the water. When he steps off, the raft oscillates for a while.

I figured out that the force constant is 21,000 Nm - first off, is that correct?

Now my QUESTION is, calculate the Frequency of oscillation (in Hz) after the man steps off the raft?


Homework Equations





The Attempt at a Solution



I came up with...

2pi sqrt (m/k)

2pi sqrt (320/21,000) = .776 Hrtz
 
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I see you used the spring equation F = kx and found the k (agree with 21000).
I have some reservations about treating this situation like a spring, but it makes considerable sense and I can't think of an alternative. Anyway, continuing with the spring model, you would use
T = 2pi sqrt (m/k)
to find the period and then the frequency.
 
Your reasoning is more important than your results.

Treated like a mass on a spring?
(75x9.8)N was enough for 3.5cm extension is 21000Nm - well done.
You plugged that into the equation for period of a mass on a spring :(

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}=\frac{1}{T}
 
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