Frequency of sound wave in air

AI Thread Summary
The velocity of sound waves in air is established at 330 m/sec. A path difference of 40 cm corresponds to a phase difference of 1.6 pi, leading to the calculation of wavelength as 0.5 meters. Using the formula for frequency, the calculated frequency of the sound wave is 660 Hz. The solution provided is confirmed to be correct. The calculations align with the principles of wave mechanics.
Amith2006
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Sir,
Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?
I solved it in the following way:
Let d(phi) = phase difference, dy = path difference
Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength
d(phi) = [2(pi)/lamda] x dy
Solving I get,
Lamda = 0.5 metre
Frequency = v/lamda
= 660 Hz
Is it right?
 
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Amith2006 said:
Sir,
Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?
I solved it in the following way:
Let d(phi) = phase difference, dy = path difference
Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength
d(phi) = [2(pi)/lamda] x dy
Solving I get,
Lamda = 0.5 metre
Frequency = v/lamda
= 660 Hz
Is it right?

Looks good to me.

~H
 
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