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Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?

I solved it in the following way:

Let d(phi) = phase difference, dy = path difference

Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength

d(phi) = [2(pi)/lamda] x dy

Solving I get,

Lamda = 0.5 metre

Frequency = v/lamda

= 660 Hz

Is it right?

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# Homework Help: Frequency of sound wave in air

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