Frequency of sound wave in air

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SUMMARY

The frequency of a sound wave in air, given a velocity of 330 m/sec and a path difference of 40 cm corresponding to a phase difference of 1.6 pi, is calculated to be 660 Hz. The wavelength (lambda) is determined to be 0.5 meters using the formula for phase difference. The calculations are confirmed to be correct by another participant in the discussion.

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  • Understanding of sound wave properties
  • Knowledge of phase difference and path difference in wave mechanics
  • Familiarity with the formula for wavelength (lambda)
  • Basic principles of frequency calculation using wave velocity
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Amith2006
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Sir,
Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?
I solved it in the following way:
Let d(phi) = phase difference, dy = path difference
Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength
d(phi) = [2(pi)/lamda] x dy
Solving I get,
Lamda = 0.5 metre
Frequency = v/lamda
= 660 Hz
Is it right?
 
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Amith2006 said:
Sir,
Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?
I solved it in the following way:
Let d(phi) = phase difference, dy = path difference
Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength
d(phi) = [2(pi)/lamda] x dy
Solving I get,
Lamda = 0.5 metre
Frequency = v/lamda
= 660 Hz
Is it right?

Looks good to me.

~H
 

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