Frequency of sound wave in air

[Amith2006]

Sir,
Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?
I solved it in the following way:
Let d(phi) = phase difference, dy = path difference
Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength
d(phi) = [2(pi)/lamda] x dy
Solving I get,
Lamda = 0.5 metre
Frequency = v/lamda
= 660 Hz
Is it right?

 

[Hootenanny]

Sir,
Velocity of sound waves in air is 330 m/sec. For a particular sound in air a path difference of 40 cm is equivalent to a phase difference of 1.6 pi. What is the frequency of this wave?
I solved it in the following way:
Let d(phi) = phase difference, dy = path difference
Here d(phi) = 1.6 pi, dy = 0.4 m, lamda = wavelength
d(phi) = [2(pi)/lamda] x dy
Solving I get,
Lamda = 0.5 metre
Frequency = v/lamda
= 660 Hz
Is it right?

Looks good to me.

~H

 

[kyle8921]

Yes, your solution is correct. The frequency of the sound wave in air is 660 Hz. This frequency is within the audible range for humans, which is typically between 20 Hz to 20,000 Hz. This calculation shows that the sound wave has a relatively high frequency, which may indicate that it is a high-pitched sound. The velocity of sound in air is often affected by factors such as temperature, humidity, and air pressure, so it is important to take those into consideration when calculating the frequency of a sound wave. Overall, your approach and solution demonstrate a good understanding of the relationship between frequency, wavelength, and velocity of sound waves in air.