Fricition: Block on inclined plane

AI Thread Summary
The discussion focuses on determining the maximum angle (theta) at which a block will not slide down an inclined plane, given a coefficient of static friction of 0.30 and no external force (||P|| = 0). Participants suggest breaking down the forces acting on the block, including gravitational force (mg) and the normal force (N). One user advises using the slope and normal components of gravity to simplify the calculations. The conversation highlights the importance of understanding static friction and force components in solving the problem. Overall, the thread aims to clarify the approach to finding the critical angle for static equilibrium.
yellowsnow
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Homework Statement


What is the maximum angle (theta) for which the block of mass m in (figure) will not slide down the incline if the coefficient of static friction is 0.30 and ||P|| = 0?

Figure:

EB2.png


Homework Equations



I know this isn't a hard problem, but I just seem to be stuck on it.

The Attempt at a Solution



I started by replacing the force "P" with it's X and Y components, then adding the 2 forces to the block, "mg" and "N", the normal force.

After that I'm stumped. I'd appreciate if anyone can help me.
 
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Welcome to PF!

Hi yellowsnow! Welcome to PF! :smile:
yellowsnow said:
What is the maximum angle (theta) for which the block of mass m in (figure) will not slide down the incline if the coefficient of static friction is 0.30 and ||P|| = 0?

I started by replacing the force "P" with it's X and Y components, then adding the 2 forces to the block, "mg" and "N", the normal force.

(do you really mean ||P|| = 0 ?)

It's a lot easier if you replace g, by its slope and normal components :wink:
 
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