- #1
waldvocm
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A block M=7.50kg is initially moving up an incline of 25.0degrees and is increasing sppeed with a= 4.44. The applied Force, F, is horizontal. The coefficients of friction between the block and incline are ms=0.443 and mk=0.312.
a) Fcos(25.0)-73.5sin(25.0)=0 F=34.3 This makes sense to me but does friction play a part in the applied force?
b) N=mgcos(25.0)+Fsin(25.0) N=81.1
c) fs=0.553*N
a) Fcos(25.0)-73.5sin(25.0)=0 F=34.3 This makes sense to me but does friction play a part in the applied force?
b) N=mgcos(25.0)+Fsin(25.0) N=81.1
c) fs=0.553*N