Friction Direction: Car Under Own Power vs. Towed

  • Thread starter Thread starter FireWarden
  • Start date Start date
  • Tags Tags
    Concept Friction
AI Thread Summary
The discussion centers on the direction of friction in two scenarios: a car under its own power and a car being towed. When a car operates independently, the static friction force acts forward, opposing the backward motion of the tires. In contrast, when a car is towed, the frictional force remains opposite to the direction of motion, meaning it still opposes the backward movement of the tires, even though the tow truck pulls the car forward. The key takeaway is that friction always acts in the direction opposite to the net force or motion, regardless of whether the car is self-propelled or towed. Understanding these dynamics is crucial for analyzing vehicle motion and frictional forces.
FireWarden
Messages
4
Reaction score
0
Does the direction of friction change based upon where the force is coming from? My brother and I are discussing it...

Specifically...if a car is operating under its own power vs. a car being towed

The two scenarios are such...

A car under its own power...the frictional force is static and positive (forward) because it is opposing the the tires going backward on the road.


For a car being towed...that is where the confusion comes in. Is it the same parameters as above, because the the friction in the opposite direction of the tires moving backwards against the road (because of the force of the towtruck pulling it forward)? The tires are still rotating after all...

Or would the friction be backwards...toward the rear of the car...because it is opposing the overall force of the towtruck moving the car forward...



Any thoughts would be great...
 
Physics news on Phys.org
The direction of the friction is always opposite the direction of motion, or the direction of the net force.
 
The friction force will be opposite to the motion and equal the frictional resistance of the driveline.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Back
Top