- #1

davidgruty

- 20

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We have a cylinder held by a rope . The rope holds it around its lower half.

If the center of mass of the cylinder is not in the middle, but towards a side, a distance "a". How does this offset affect to the friction on the rope?

or

How big does "a" have to be so the cylinder starts moving?

The weight of the cylinder "P" goes downwards. But the friction is along the lower half of it. Can one sum the moments around the center?

P*a=N*mue*R {1}

N: reaction force along the rope

mue: static friction coeficient

R: cylinder radius

In general:

P=mue*N {2}

I can't combine these two

How can I calculate "a"?

thanks