Hello, I'm doing work in Fuel Cells and am having difficulty with a simple issue; the Nernst Voltage (E) is greater than the Standard Potential (E(adsbygoogle = window.adsbygoogle || []).push({}); ^{O})

The only electrochemical reaction considered is H_{2}+ 0.5O_{2}--> H_{2}O

The Nernst equation for this reaction is

E = E^{O}- (RT / 2F) ln (PH2O / (PH2 * SQRT(PO2))

'Anode In' composition is 2.78 slpm H_{2}and 0.049 sccm H_{2}O; at about 1 atm

'Cathode In' is air supplied at 8.34 slpm, at about 1 atm

When I calculate the pressures, I get

P H2O = 0.00619 kPa = 6.19 Pa

P H2 = 101.319 kPa = 101319 Pa

P O2 = 21.28 kPa = 21280 Pa

which gives me roughly ln(10^-7), thus apositive lossof roughly 0.65 V (while running at approximately 1028 K).

Thanks for any help.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Fuel Cell Voltage Calculation

**Physics Forums | Science Articles, Homework Help, Discussion**