Full Wave Rectifier: Get Answers to Your Questions

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In a full wave rectifier setup, when a sine wave is applied, only half of the secondary coil of the transformer is utilized at any given time, depending on the polarity. The diodes in the circuit allow current to flow through only one half of the secondary coil during each half-cycle of the input signal. Both halves of the secondary have the same potential drop, but only one loop's current can flow at a time. This means that while both halves are capable of carrying current, only one is active based on the input polarity. Understanding this mechanism is crucial for effectively using full wave rectifiers in circuits.
cupid.callin
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Hi all

attachment.php?attachmentid=47010&stc=1&d=1336314638.jpg


So my question is, ...
suppose we apply sine wave at the 2 ends, th the cycle 0 \rightarrow \pi will all the coils of secondary coil of transformer be used or just upper half of it (assuming currently upper side is getting positive polarity) ...
I think only half should be used ...

Any help?
 

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"Used" is a bit vague, but if you mean that current will flow only in the upper half of the secondary for the indicated polarity then yes, only half of the secondary is "used" at a time. Note that while both halves of the secondary will have the same potential drop across them the diodes will permit only one of the loops currents to flow depending upon the polarity.
 
gneill said:
"Used" is a bit vague

:-p


gneill said:
but if you mean that current will flow only in the upper half of the secondary for the indicated polarity then yes, only half of the secondary is "used" at a time. Note that while both halves of the secondary will have the same potential drop across them the diodes will permit only one of the loops currents to flow depending upon the polarity.

Ah! That's all I wanted to know !
Thanks again for your help gneill !
 

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