Functional analysis and limits

[dirk_mec1]

Homework Statement

http://img357.imageshack.us/img357/8695/38808719uw6.png

Homework Equations

\lim_n a_n := \lim_{n \rightarrow \infty} a_n

The Attempt at a Solution

I'm stuck at exercise (c). Since if n heads to infinity the m doesn't play the role the limit must be one. So the mistake is somewhere on the left and I think it is at the part where both limits are taken at the same time.

Or is the limit 1/2? Can someone help me?

 

[Dick]

Does f_n really converge to 1? What's ||f_n-1|| for any n?

 

[morphism]

Hint: we have to be careful when we say things like "f_n \to \textbf{1}[/tex]" nonchalantly. What does "\to" mean in this setting?

 

[dirk_mec1]

Does f_n really converge to 1? What's ||f_n-1|| for any n?

||f_n-1|| = \frac{m}{m+n} for any n. But if I let n tend to infinity this would go to zero, right? So the limit is one? I guess I miss the point here because the n stands for the n^th sequence and the m is just the element in that sequence, right?

If I look in one sequence (so for fixed n) and let m tend to infinity I would always get zero do you mean that?

Hint: we have to be careful when we say things like "f_n \to \textbf{1}[/tex]" nonchalantly. What does "\to" mean in this setting?

<br /> <br /> It means keeping m fixed while letting n \rightarrow \infty right?

 

[Dick]

Don't take n to infinity. Just focus on a single n for a minute. I think the limit m->infinity of m/(m+n) is one, not zero. So I would say ||f_n-1||=1. For ALL n. So I would say while it converges pointwise, the sequence f_n does not converge in l_infinity.

 

[dirk_mec1]

Don't take n to infinity. Just focus on a single n for a minute. I think the limit m->infinity of m/(m+n) is one, not zero. So I would say ||f_n-1||=1. For ALL n.

So there holds: \lim_{m \rightarrow \infty} f_n =1 imlpying pointwise convergence.

So I would say while it converges pointwise, the sequence f_n does not converge in l_infinity.

A sequence converges in l^{\infty} if \lim_{j \rightarrow} ||f_j-f||_{\infty} \rightarrow 0 but by noticing the pointwise convergence one can note that this will not head to zero but 1, right?

 

[Dick]

I think you've got the right idea. I think your first statement should say lim n->infinity f_nm=1. Each term m of the sequences tends to 1 as n->infinity. But that's not enough to make the f_n converge.