Proving the Fundamental Group of SO(2) is Z: How Can it Be Done Explicitly?

Davidedomande
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Good morning. I was wondering how do you prove explicitly that the fundamental group of SO(2) is Z?
 
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Prove it's homeomorphic to the circle.
 
If i remember correctly complex numbers of unitary norm can be represented as 2x2 orthogonal matrices. I could use that to prove the statement right?
 
Yes
 
Thank you very much!
 
One of the easiest ways to prove [what the fundamental group of a space is] is to find its universal covering space and determine the group of covering transformations (sometimes called "deck" transformations).

Doing that for the case of SO(2) is about the same amount of work as proving SO(2) is homeomorphic to the circle. But determining the group of covering transformations ends up proving that π1(SO(2)) ≈ , instead of just relying on some previous theorem about the fundamental group of the circle.
 
A sphere as topological manifold can be defined by gluing together the boundary of two disk. Basically one starts assigning each disk the subspace topology from ##\mathbb R^2## and then taking the quotient topology obtained by gluing their boundaries. Starting from the above definition of 2-sphere as topological manifold, shows that it is homeomorphic to the "embedded" sphere understood as subset of ##\mathbb R^3## in the subspace topology.
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