Fundamental theorem of algebra

ehrenfest
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Homework Statement


There are two versions of the fundamental theorem of algebra, one that says a polynomial of degree n has n roots and the other that says a polynomial can be factored into linear and irreducible quadratic factors. Is there a quick way to see how they are the same?


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The Attempt at a Solution

 
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The 2nd version is talking within the real numbers ie A polynomial with real coefficients can be factored into linear and irreducible quadratic factors over R.

The first version is the same because the factor theorem says that for P(x), if g is a root then (x-a) is a factor. We can use the quadratic formula too see that any quadratic factor can be factored into linear factors, if factored over C instead of R.
 
I see why the second version implies the first version. I do not see why the first version implies the second version.

How do you know that you can get rid of all of the factors (x - a) where a is complex, since the 2nd version really says that A polynomial with real coefficients can be factored into linear and irreducible quadratic with real coefficients.
 
O yes I forgot about that implication. Remember the complex conjugate theorem, which states the for polynomials with real coefficients, complex roots will come in conjugate pairs.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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