- #1

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This is something I can churn through mechanically but I never "got." Any links / explanations that can help build my intuition about this would be helpful.

- Thread starter e^(i Pi)+1=0
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- #1

- 245

- 0

This is something I can churn through mechanically but I never "got." Any links / explanations that can help build my intuition about this would be helpful.

- #2

Mark44

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What you have is incorrect, assuming that both a and b are constants.[itex]\frac{d}{dx} \int_a^b f(x)=f(b)[/itex]

This is something I can churn through mechanically but I never "got." Any links / explanations that can help build my intuition about this would be helpful.

[tex]\frac{d}{dx} \int_a^b f(x) dx =0[/tex]

The way this is usually presented is like so:

[tex]\frac{d}{dx} \int_a^x f(t) dt =f(x)[/tex]

- #3

Mark44

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Then

$$ \int_a^x f(t) dt = F(x) - F(a)$$

So $$ d/dx \int_a^x f(t) dt = d/dx( F(x) - F(a)) = F'(x) - 0 = f(x)$$

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