G Parity Operator Calculation for Neutral and Charged Pion States

[kakarukeys]

why G parity = (-1)^I C?
C is the Charge conjugation number of the neutral member.

G parity of \pi^0 is very obvious. Given e^{i\pi I_2} |I\ 0\rangle = (-1)^I |I\ 0\rangle

How do you compute the G parity of \pi^+?

G parity operator
G = Ce^{i\pi I_2}

 

[marlon]

Look at http://ej.iop.org/links/q19/gde,d+XMMgTmN65bCrJ,UA/ejv11i2p99.pdf
or
http://www.phys.uAlberta.ca/~gingrich/phys512/latex2html/node64.html

Charge conjugation is determined by how physical entities (like the E field) change if you replace a charge by its opposite(this is what the charge conjugation operator does)...For example E will be come -E if you replace q by -q

marlon

to see how it is done : www.physics.ohio-state.edu/~kass/P780_L6_sp03.ppt