Gauss' Law and a Gaussian Sphere

AI Thread Summary
A Gaussian sphere with a radius of 1m surrounds an unknown charge, producing a uniform electric field of 1 N/C at its surface. To find the enclosed charge, Gauss' Law can be applied using the equation E = q/(4∏ε₀r²). The confusion arises regarding whether the charge inside a Gaussian sphere can be zero; it is not always zero, especially when an electric field is present. The electric field inside a conductor is zero, but this does not apply to the Gaussian sphere in question. Therefore, the charge can be calculated using the provided electric field and radius.
victorializ
Messages
20
Reaction score
0

Homework Statement


A Gaussian Sphere with a radius of 1m surrounds an unknown charge at the center. At this surface a uniform outward directed electric field is 1 N/C. Use Gauss' Law to calculate the amount of charge enclosed by the sphere.

Homework Equations



E = q/4∏εor^2

The Attempt at a Solution



i've been reading about gauss' law in my physics book and i thought that the charge inside a gaussian sphere was always zero? or is that only for an electric field?
 
Physics news on Phys.org
victorializ said:

Homework Statement


A Gaussian Sphere with a radius of 1m surrounds an unknown charge at the center. At this surface a uniform outward directed electric field is 1 N/C. Use Gauss' Law to calculate the amount of charge enclosed by the sphere.


Homework Equations



E = q/4∏εor^2

The Attempt at a Solution



I've been reading about gauss' law in my physics book and i thought that the charge inside a Gaussian sphere was always zero? or is that only for an electric field?
The Electric Field (under static conditions) is zero within the conducting material of a conductor. A Gaussian surface is simply any closed surface over which it is convenient to apply Gauss's Law.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top