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Gauss on a conduction sphere.

  1. Oct 18, 2006 #1
    Ok for example, if a solid conduction sphere was charged to 500volts and had radius of 1cm. Then charge, Q = VR = 5?

    So the E field just outside the sphere would be E = (1/4pi epsilon) x charge/R^2 = 4.5 x 10^14?

    Or am i getting confused?
  2. jcsd
  3. Oct 18, 2006 #2


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    Just check your units. The E field anywhere outside the sphere is inversely proportional to r^2. You can find E just outside the surface, or anywhere else outside.
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