Two identical conducting spheres each having a radius of 0.460 cm are connected by a light 1.20 m long conducting wire. Determine the tension in the wire if 69.2 (micro)C is placed on one of the conductors. (Hint: Assume that the surface distribution of charge on each sphere is uniform.) Round your answer to three significant figures. Take the Coulomb constant to be K_e = 8.99 *10^9 N*m^2/C^2 E = K_e (q/r^2) Field on conducting sphere (needed to produce force on string) E = (1/2*[tex]\Pi[/tex]*[tex]\epsilon[/tex]) q/r^2 Field on -infinite- charged wire (where Epsilon = 8.854*10^-12 C^2/N*m^2) Force = qE So far I'm fairly stumped by this problem, though I've been applying Gauss' Theorum most of this afternoon... The charge must be distributed symmetrically, first throughout the sphere in which it is placed. I can solve for the charge at the surface of the first sphere to get something like 2.94 * 10^10 N-C. From here, I'm thinking the positive charge will be distributed through the conducting wire to the other sphere equally... So each sphere will end up having the same surface charge density and field, which produces a tension on the wire. Even some conceptual help here would be thoroughly appreciated. Thanks.