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tgt
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Would the GCD of x^2+x+c and (x-a)^2+(x-a)+c always be 1?
tgt said:Would the GCD of x^2+x+c and (x-a)^2+(x-a)+c always be 1?
tgt said:So it seems that two polynomials have nonzero GCD when there is at leaste one root shared between the two. So any two polynomials of the form a(x-t)^2+b(x-t)+c and ax^2+bx+c must have GCD 1 since they wouldn't have any roots shared between them.
tiny-tim said:What about x2 + 3x + 2 = 0 and (x + 1)2 + 3(x + 1) + 2 = 0?
The GCD (Greatest Common Divisor) of polynomials is the highest degree polynomial that can divide evenly into both polynomials with no remainder. It is also known as the highest common factor.
No, 1 is not always the solution for the GCD of polynomials. It depends on the polynomials being evaluated. In some cases, the GCD may be a different constant or even a polynomial.
The GCD of polynomials can be found using the Euclidean algorithm, which involves dividing the larger polynomial by the smaller one until the remainder is zero. The last non-zero remainder is the GCD of the two polynomials.
Yes, the GCD of polynomials can be negative. The GCD is a factor of both polynomials, so it can be positive or negative depending on the factors of the polynomials being evaluated.
Finding the GCD of polynomials can help simplify and factorize complex polynomials. It can also be used in various mathematical operations, such as finding common denominators or solving equations.