Gear Train Design for 300 ft/min Conveyor at 1760 RPM Motor

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The discussion focuses on designing a gear train for a belt conveyor driven by a motor operating at 1760 RPM, requiring the conveyor to run at 300 feet per minute. The calculated RPM for the conveyor is 95.5, leading to a necessary gear ratio of 18.4. The original proposal involves a simple two-gear design, but finding suitable gears on McMaster-Carr that achieve this ratio has proven challenging. There is a suggestion to consider a three-gear setup to maintain each gear ratio under 10:1. The feasibility of using a worm gear is questioned, as it typically converts high speeds to low speeds, which may not be applicable in this case.
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Homework Statement


A belt conveyor with a 1-foot diameter is driven by an electric motor. The conveyor must travel at 300 linear feet per minute while the motor turns at 1760 RPM. Design a gear train to connect the motor and conveyor and choose gears from McMaster-Carr.


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The Attempt at a Solution


I calculated the RPM of the conveyor to be 95.5 RPM. I thought the simplest design would be if there was a compound gear on the shaft of the conveyor and the shaft of the electric motor, giving a simple two gear design. However, the calculated gear ratio is 18.4 and I cannot find two gears on the McMaster-Carr website that would give me that gear ratio. I read somewhere that between two spur gears the highest gear ratio is usually 10:1. I don't think a worm gear applies because that is for converting a high speed to a very low speed. Is that correct, or is 95.5 RPM sufficiently slow?
 
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Have you considered 3 gears?

Looks possible and keeps each stage <10:1

PS I haven't actually checked the website to see if the right gears exist.
 
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