General Application of Boyle's Law

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Boyle's Law states that the product of pressure and volume for a given mass of gas remains constant when temperature is unchanged. In the scenario presented, the initial volume of air is 200 cm³ with a mass of 120 grams on the piston, which changes to 250 cm³ when the mass is removed. To find the mass of the piston, one must analyze the relationship between the pressures before and after the block is removed, applying the formula P1V1 = P2V2. The pressure change relates directly to the mass of the piston and the block, indicating that the piston must exert a force equal to the weight of the block to maintain equilibrium. Understanding these relationships allows for the calculation of the piston's mass based on the changes in volume and pressure.
huzi94
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Hello,
I am Year 10 student and would like to get help on the question below based on Boyle's Law.

A piston with a block of mass 120 grams placed on it traps 200cm³ of air in a container. When the block is removed, the volume becomes 250cm³. Find the mass of the piston.

In the question above i only know that you have to use the formula P1V1=P2V2, but i don't know how to apply it. Please can anyone help?
 
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The formula means that if you have a quantity of gas with pressure P1 and volume V1, and you compress it, or let it expand, and afterwards the pressure and volume are P2 and V2, then
P1V1 = P2V2

you know the volume before and after removing the block. What can you say about the pressure, and how is this related to the mass of the block and the piston.
 

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