General solution of differential equation system

mansfin
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Homework Statement



Find the general solution of the system of differential equations
x'=10x - 12y
y'=25x - 30y
(where primes indicate derivatives with respect to t) by using the initial conditions
x(0)=A
y(0)=B

Homework Equations



The Attempt at a Solution



x''=10x' - 12y'
y'=25x-30y
x''=10x'-12(25x-30y)
y=\frac{10x-x'}{12}
x''=10x'-300x+360(\frac{10x-x'}{12})
x''=10x'-300x+300x-30x'
x''+20x'=0
r^2+20r=0
r(r+20)=0
r=0,-20
x(t)=Ae^{-20t} +B \rightarrow x(0)=A
A=A+B
B=0
y=\frac{10x-x&#039;}{12}=\frac{5}{2}Ae^{-20t} \rightarrow y(0)=B<br /> 0=\frac{5}{2}A<br /> A=0<br /> <br /> If A=0 and B=0, then my general solutions x(t),y(t)=0. This is clearly not right. What am I doing wrong? Thanks!
 
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Use C and D in your general solution so they don't get mixed up with the A and B in the initial conditions.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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