General Tensor contraction: Trace of Energy-Momentum Tensor (Einstein metric)

tetris11
Messages
22
Reaction score
0
Okay so I have:

Eqn1) Tij=\rhouiuj-phij = \rhouiuj-p(gij-uiuj)

Where Tij is the energy-momentum tensor, being approximated as a fluid with \rho as the energy density and p as the pressure in the medium.


My problem:
Eqn2) Trace(T) = Tii = gijTij = \rho-3p

My attempt:

Tr(T) = Tii = gij[\rhouiuj-p(gij-uiuj)]
= [\rhogijuiuj-pgijgij+pgijuiuj)]
= \rhou - p + pu

which doesn't equal rho-3p (eqn2) as required, so I've done something wrong.
I think I've contracted incorrectly but I don't know why... please help?
 
Physics news on Phys.org
What are the following?

g^{i j} g_{i j} = ?

g^{i j} u_i u_j = ?
 
Well,
g^{i j} u_i u_j = 1

g^{i j} g_{i j} = ??
uh... g? or 0?

Might need to help me out here, maths isn't my first language...
 
Cheers man, that actually makes complete sense - but just for the record:

gij gij = δii = n, where n is number of dimensions?

I'm just wondering how you knew it was four without knowing how dimensions it was.
Tensors aren't all 4-d, right?
 
tetris11 said:
Cheers man, that actually makes complete sense - but just for the record:

gij gij = δii = n, where n is number of dimensions?

I'm just wondering how you knew it was four without knowing how dimensions it was.
Tensors aren't all 4-d, right?

Well this is the 'Special & General Relativity' board so it was probably just a good guess?
 
Thread 'Can this experiment break Lorentz symmetry?'
1. The Big Idea: According to Einstein’s relativity, all motion is relative. You can’t tell if you’re moving at a constant velocity without looking outside. But what if there is a universal “rest frame” (like the old idea of the “ether”)? This experiment tries to find out by looking for tiny, directional differences in how objects move inside a sealed box. 2. How It Works: The Two-Stage Process Imagine a perfectly isolated spacecraft (our lab) moving through space at some unknown speed V...
Does the speed of light change in a gravitational field depending on whether the direction of travel is parallel to the field, or perpendicular to the field? And is it the same in both directions at each orientation? This question could be answered experimentally to some degree of accuracy. Experiment design: Place two identical clocks A and B on the circumference of a wheel at opposite ends of the diameter of length L. The wheel is positioned upright, i.e., perpendicular to the ground...
According to the General Theory of Relativity, time does not pass on a black hole, which means that processes they don't work either. As the object becomes heavier, the speed of matter falling on it for an observer on Earth will first increase, and then slow down, due to the effect of time dilation. And then it will stop altogether. As a result, we will not get a black hole, since the critical mass will not be reached. Although the object will continue to attract matter, it will not be a...
Back
Top