Generator start-up torque

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The discussion focuses on calculating the torque for a starter generator (СГ-18-1С) rated at 18 kW and operating between 3600 to 6200 RPM. Initial calculations suggest a torque of approximately 48 Nm at 4000 RPM, but further analysis indicates a maximum applied shaft torque of 125 Nm is possible. The calculations confirm that the output power translates to around 24.13 HP, leading to a torque of about 43 Nm at 4000 RPM when considering efficiency losses. The generator is designed for starting diesel engines and supplying electric energy, with a maximum current of 800 amps. Accurate torque calculations are crucial for selecting an appropriate motor for the application.
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Torque calculation of СГ-18-1С
Hi
I want to design a test rig for starter generator ( СГ-18-1С ). The output of the starter generator is 28V, 18KW @ rpm 3600 - 6200. The output will be regulated through excitation winding current.

I want to choose a motor to run the stater generator. Please tell me, How to calculate the torque of the starter generator.

I calculated as Torque = Power x 60 / 2 x Pi x rpm, results a ~48Nm torque at 4000 rpm. Is it correct or need to consider the excitation winding current? Please suggest. I want to choose the motor using V- belt pully drive with step up.

Thank you
 
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1 HP = 746 Watts
18KW / 746

18 000/746 = 24.13 HP

HP x 5252 /rpm = Torque (Ft.Lbs.)
24.13 x 5252 / 4000 = 31.68 FtLbs

1FtLb = 1.356 Nm
31.68 x 1.356≅ 43Nm

That assumes 100% efficiency in the starter and the belts, which of course will not happen.

Cheers,
Tom
 
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Welcome to PF.

The SG-18-1S starter/generator is a Russian built direct current machine of mixed excitation, with air cooling by a built-in fan, designed for starting of diesel engines, supplying electric energy, and recharging batteries.

Specified as 18 kW.
Generator maximum current: 800 amp continuous. ( Vmax of 22.5 volt ).
Maximum applied shaft torque = 125 N∙m.
Maximum speed 7000 RPM.

To generate the maximum output will require an engine rating of 18 kW.
18 kW is equivalent to 24 HP.

4000 RPM * 0.10472 = 418.9 radian/sec.
18 kW / 418.9 = 43.0 N∙m.
My numbers agree with Tom.G

For 18 kW output, shaft torque will be;
@ 3600 RPM, 48. N∙m
@ 4000 RPM, 43. N∙m
@ 4400 RPM, 39. N∙m
@ 5200 RPM, 33. N∙m
@ 6000 RPM, 29. N∙m
 
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