Geometric Series Test Rather Than Integral Test

Bashyboy
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Homework Statement


\sum_{n=1}^{\infty} \frac{1}{2^n}


Homework Equations





The Attempt at a Solution


Could I some how manipulate this to fit a geometric series, so that I may instead use the geometric series test?
 
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\frac{1}{2^n}= \left(\frac{1}{2}\right)^n
 
Bashyboy said:

Homework Statement


\sum_{n=1}^{\infty} \frac{1}{2^n}

Homework Equations



The Attempt at a Solution


Could I some how manipulate this to fit a geometric series, so that I may instead use the geometric series test?

Hint:

No manipulation is required.
 
Well, I was told by my teacher that n couldn't equal one for the geometric series to be implemented, was he, perhaps, wrong?
 
Bashyboy said:
Well, I was told by my teacher that n couldn't equal one for the geometric series to be implemented, was he, perhaps, wrong?
Do you mean, n can't start at 1, it must start at zero?

If so factor 1/2 out of your series & change the index accordingly,

else,

Add 1 to your series so that it starts at n=0, and subtract 1 from your result.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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