- #1
Bashyboy
- 1,421
- 5
[itex]\stackrel{\rightarrow}{PQ}[/itex] bisects [itex]\angle{ABC}[/itex].
If [itex]m\angle{ABD}[/itex] can be represented by [itex]3a + 10[/itex] and [itex]m\angle{DBC}[/itex] can be represented by [itex]5a - 6[/itex], what is [itex]m\angle{ABC}[/itex]?
What I did was add the two representations together and multiplied by two, which would give me [itex]16a + 8[/itex]. Does that sound correct?
If [itex]m\angle{ABD}[/itex] can be represented by [itex]3a + 10[/itex] and [itex]m\angle{DBC}[/itex] can be represented by [itex]5a - 6[/itex], what is [itex]m\angle{ABC}[/itex]?
What I did was add the two representations together and multiplied by two, which would give me [itex]16a + 8[/itex]. Does that sound correct?