Geometry question form ax^2+bx+c

AI Thread Summary
The discussion revolves around a geometry question involving the areas of four rectangles defined by variables a, w, and h. The correct answer is identified as C, with the equations aw + ah = 25a and w + h = 25 being central to the problem. Participants clarify that individual values for w and h are not necessary to solve for the perimeter, which can be expressed using the given relationships. The tutor realizes they were overlooking a straightforward aspect of the problem. Ultimately, the conversation highlights the importance of recognizing relationships between variables in geometry questions.
Daaniyaal
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I was tutoring a student and I came across the following question. I feel like I'm missing something obvious, but it seems like there are too many variables for an answer to be determined. The attached picture contains all of the question details.
 

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The correct answer is C by the way
 
Let w = width of the upper right rectangle, and
let h = height of the lower left rectangle.

Then the areas of the four rectangles, going clockwise from the upper left are a2, aw, ah, and 144.

What must the areas of the upper right and lower left rectangles add up to?
What's an expression that gives the perimeter?

I get C as the answer as well.
 
aw+ah=25a
w+h=25

how do i determine the individual values of w and h?
 
Daaniyaal said:
aw+ah=25a
w+h=25

how do i determine the individual values of w and h?
You don't have to. You have w + h = 25. Now write an expression for the perimeter.
 
oh thanks! I got it :) I was missing the obvious >.<
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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