Getting an average figure with ±

  • Thread starter Thread starter Monocerotis
  • Start date Start date
  • Tags Tags
    Average Figure
AI Thread Summary
To calculate an average value with uncertainties, it's essential to consider the precision of each measurement. The initial method proposed incorrectly combined the uncertainties, leading to an inaccurate result. A weighted mean approach is recommended, especially when measurements have different levels of precision. The discussion highlights the importance of understanding whether the measurements are statistically independent and how to properly calculate combined uncertainties. Clarifying the context of the measurements can further aid in determining the correct method for averaging.
Monocerotis
Gold Member
Messages
54
Reaction score
0

Homework Statement



Quick question, working on a lab

Just wondering how I could go about getting an average value for a series of figures with +- values.

For instance
1) 1.5 ± 0.02
2) 1.7 ± 0.84
3) 1.7 ± 0.08

The Attempt at a Solution



I tried enclosing the figures within parenthesis and then trying to find an average with wolfram alpha but no success.

I was just reading something on the net

would it be x "avg" ± Δx "avg

1.5 + 1.7 + 1.7 /3 = 1.63
(sqrt) 0.02^2 + 0.84 + 0.08 = 0.844

so we arrive at 1.63 ± 0.844

correct ?
 
Physics news on Phys.org
Monocerotis said:
would it be x "avg" ± Δx "avg

1.5 + 1.7 + 1.7 /3 = 1.63
(sqrt) 0.02^2 + 0.84 + 0.08 = 0.844

so we arrive at 1.63 ± 0.844

correct ?
Incorrect, and very much so. Assuming the measurements are statistically independent (are they? There's no telling from the original post) then

1. That 1.5 measurement is considerably more precise than either of the other two measurements. You should get something closer the 1.5 than 1.7 for your final estimate.

2. You combined error is larger than the largest error. It should be smaller than any of individual errors.Google "weighted mean".
 
k I've been reading and it seems as though what I'm dealing with is a common mean rather than a weighted mean

I'm dealing with slope figures of a v(t) graph and trying to find g avg +- delta g avg as to compare it with my theoretical results

the values I gave above were ambigous but the figures I'm actually dealing with from my perspective appear to have equal weight so

still confused as to what to do however because even the common mean will only give me a single value
 
What exactly are you measuring here? Without details it is a bit hard to help you.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top