- #1
jaydnul
- 558
- 15
I was reading the derivation of capacitor reactance and I understand it up to the point where it is converted to polar coordinates. How do you get from
[tex]X=\frac{sin(wt)}{wCcos(wt)}[/tex]
to
[tex]X=\frac{1}{jwC}[/tex]
This implies that
[tex]\frac{sin(wt)}{cos(wt)}=-j[/tex]
And I'm confused how that is derived.
Thanks
Edit: reactance is X not Z
[tex]X=\frac{sin(wt)}{wCcos(wt)}[/tex]
to
[tex]X=\frac{1}{jwC}[/tex]
This implies that
[tex]\frac{sin(wt)}{cos(wt)}=-j[/tex]
And I'm confused how that is derived.
Thanks
Edit: reactance is X not Z