Given 2n objects, number of ways to select n objects

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Homework Statement


Given N identical objects and N additional objects that are different from these and from each other, find the number of ways to select n objects out of these 2N objects.


Homework Equations


Either P(n,k) or C(n,k) or n^k or maybe even (n+k+1)/k


The Attempt at a Solution


Looking at these...so half the set is identical and the other half is distinct from the first half and from them selves. So I will call the first set S and the second set T to help me keep them apart.
So for the first set everything is identical and w can select up to N of them... my notes seem to indicate i would go about it as (S+N+1)/N and then the second set they are distinct from each other and we can select N of them, so T^N? Are those two formulas in the right direction? If so would I multiply those together to get the correct answer?
 
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Just count them. Number of ways to select n of A, 0 of B is 1.
n-1 of A, 1 of B is n
n-2 of A, 2 of B is n(n-1), etc.

So you get sum{i=0..n}(n choose i) = 2^n.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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