Given a polynomial p, prove A^2-B^2 = p(1)p(-1)

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Homework Statement


Given a polynomial p, let A be the sum of the coefficients of the even powers, and let B be the sum of the coefficients of the odd powers. Prove that A^2 - B^2 = p(1)p(-1).

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The Attempt at a Solution


See attached. Can someone please look at my work to see if it is correct. Best!
 

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Your solution is correct but limited. Can you show this to be true for an arbitrary number of terms ##N## without going through all the tediousness of your method? Generous hint: Can you express A and B in terms of P(1) and P(-1)?
 
Well that was a lot easier! Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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