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show x-1 is factor :

f(1)=0

1+4-5=0 Thus it's a factor.

express in form (x-1)(x^2+px+q)

ends up being X^2 + X + 5.

next question is :

hence show the equation f(x) = 0 has one real root state it's value.

i know i have to use b^2 -4ac. If i do that it's -19 which is <0 so it's 1 value. But how do I find the value. And why does all this stuff work.

My teacher is one that just tells you how to do it. I have no idea why i'm doing it and it makes no sense so it's harder to remember. I would get 1or 2 marks out of 3 for this.

Firstly i dont know how to find out what the real number is. and i don't know why this works.

explain plez?! 8D